notes/science/algebra/group/people/alexandrov.txt
Ihar Hancharenka 5dff80e88e first
2023-03-27 16:52:17 +03:00

133 строки
2.9 KiB
Plaintext

Alexandrov - Groups Theory Intro.djvu
Page 33.
(ab)^-1 = b^-1*a^-1
ab(b^-1a^-1) = a(bb^-1)a^-1 = aa^-1 = 1
Page 85.
Group element b^-1ab is called a "transformation of a using b".
When does the following holds???
a = b^-1ab
Iff (if and only if) the elements commute:
ab = ba
Multiplying left by b^-1 having:
b^-1ab = a
Lema 1 (Conjugation elements symmetry)
If elt-b is a transformation of elt-a using elt-c
b = c^-1ac
Then elt-a is a transformation of elt-b uscing elt-(c^-1):
cbc^-1 = a
a = (c^-1)^-1bc
Def (Conjugate elements)
If one group element is a transformation of the other - they are called conjugant.
Lema 2 (Conjugate elements transitivity).
If elt-a is adjoint with elt-b, which is adjoint with elt-d,
then elt-a is ajdoint with elt-d.
b = c^-1ac
b = e^-1de
So,
c^-1ac = e^-1de
a = (ce^-1)d(ec^-1) = { p. 33.} = (ec^-1)^-1d(ec^-1)
In other words, a is a transformation of d usint elt-(ec^-1).
Lema 3 (Adjoint elements reflexivity)
Every elt-a is adjoint to itself:
a = 1^-1a1
Theorem 1 (Conjugacy classes)
Conjugant relation splits group G to the set of equivalence-classes.
Note: Class of neutral el-t 1 consists only of 1-itself:
a^-1*1*a = 1 for all a
Def (subgroup transformation)
Conside H - subgroup of G.
Let's fix some el-t b of G.
We call group transformation b^-1Hb a set of
b^-1Hb = { b^1xb | x of H }
We can prove (p. 91) that b^-1Hb is indeed a group.
It is obvious that H is isomorphic to b^-1Hb.
Theorem 2.
Transformation of subgroup H (of group G) using el-t b of G
is a subgroup of G, isomorphic to H.
Note 1: If H is a subgroup of commutative/abelian group G.
then subgroup transformation of H using any b of G is H itself
b^-1xb = {commutativity} b^-1bx = x
Note 2: For every group G and subgroup H, if b belongs to H, then
b^-1Hb = H
since b^-1xb belongs to H
Note 3: If subgroup H_2 is a transformation of H_1 using b,
then H_1 is a transformation of H_2 using b^-1
Def (Conjugative subgroups)
Two subgroups of group G are called conjugative if one of them is a transformation of another.
Conjugation relation splits subgroups to the equivalence-classes.
Invariant/Normal subgroup
Def 1. If subgroup H of G has no conjugative subgroup (except itself), then it is called
normal or invariant subgroup.
In other words - transformation of any element of H, using any element of G, belongs to H.
Example: any subgroup of commutative-abelian group is normal/invariant.
Homomorphisms and Kernel
Page 97...
Page 99.
Kernel of homeomorhic group morphism:
f : A -> B
f(ab) = f(a) f(b)
if the set
a of A, such that
f(a) = 1_B
In other words, Kernel(f) = f^-1(1_B).
Page 111 - Factor groups...
Page 113.
If U is some normal/invarian gubgroup of G, the set of equivalence-classes V
is a group itself (U is a neutral element).
Group V is called a factor-group of G.